A jet aircraft is traveling at 246 m/s in horizontal flight. The engine takes in air at a rate of 77.0 kg/s and burns fuel at a rate of 4.00 kg/s. If the exhaust gases are ejected at 633 m/s relative to the aircraft, find the thrust of the jet engine and the delivered power
calculate thrust and power
i tried quite a bit...but cant get it, now can my instructor
Since the air and fuel are both ejected, the mass ejection rate dm/dt is 77.0 + 4.00 kg/s. Thrust = v*dm/dt = 633*81 = 61273 N
Power = Thrust*velocity = v²*dm/dt = 32.5*10^6 W
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