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| How to solve for the systems of equations? | | Published by: admin 2008-10-24 |
| | 1. 5^(x+2y) = 10 ; x-y=3
2. 4^(x+y) = 60 ; 3^(x-y) =5
[5 exponent (x+2y) 4 exponent x+y]
how do i solve these? and please explain each step. thanks! Addition Method:: The whole problem with solving a system of equations is that you cannot solve an to substitute this value into one of the original equation to solve for http://www.jamesbrennan.org/algebra/systems/addition_method.htmHOME | Algebra II: Coordinate Geometry - Math for Morons Like Us:: The easiest way to solve systems of equations that include circles, ellipses, or 1. Problem: Solve the following system of equations: x2 + y2 = 25 3x - 4y = 0 http://library.thinkquest.org/20991/alg2/geo.htmlHOME |
Ques 1:
5^(x + 2y) = 10
Take log on both sides, we get
(x + 2y) log 5 = log 10
x + 2y = log 10 / log 5
the second equation is x - y = 3 Math Forum - Ask Dr. Math:: How do you solve this system of equations by graphing: 3x + 2y = 5 and - 3x - 2y = 10? a value for x and then determine the value of y required to satisfy http://mathforum.org/library/drmath/view/54467.htmlHOME |
2x - 2y = 6
Adding the first to this, we get
3x = log 10 / log 5 + 6
x = log 10 / (3 log 5) + 2
y = x - 3
= log 10 / (3 log 5) - 1
Ques 2:
4^(x + y) = 60
Taking log
(x+y) log 4 = log 60
Also,
x - y = log 5 / log 3
2x = log 60 / log 4 - log 5 / log 3
you can solve further from this
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