how do i solve for X in the following using common log in terms of Y:
1. y= (10^x+10^-x)/2
2. y= (10^x+10^-x)/(10^x-10^-x)
3.y= 0.5^x+1 < 32 < 0.25^x
4. (1/9)^x + (1/3)^x > 2
can you please give me a clear solution and explain how to solve each?
Solve Website Scanning and Crawling Problems::
Jun 22, 2007 Solve broken links and broken redirects. Server errors, broken redirects and broken links are common problems which before in time would
http://www.micro-sys.dk/developer/articles/website-scan-crawl-problems.phpHOME |
How to solve Windows system crashes in minutes - Network World::
Apr 19, 2005 Using a tool that costs nothing, you can solve approximately 50% of It's common to see weeks and months pass before the answer is found.
http://www.networkworld.com/news/2005/041105-windows-crash.htmlHOME |
thanks!
y = [ 10^x + 10^(-x) ] / 2
Let's solve for x.
First, multiply both sides by 2, to get
2y = 10^x + 10^(-x)
Express 10^(-x) as 1/10^x.
2y = 10^x + [1/10^x]
Multiply both sides by 10^x, to get
Logarithms Through Applications::
File Format: PDF/Adobe Acrobat - View as HTMLYour browser may not have a PDF reader available. Google recommends visiting our text version of this document.Students should know the difference between common log. and natural log, but realize that .. Using the compound interest formula and logarithms, find how
http://www.ma.iup.edu/MAA/proceedings/vol1/frank/frank.pdfHOME |
Using ‘Software to Solve Problems in Large Computing Courses::
Your browser may not have a PDF reader available. Google recommends visiting our text version of this document.Using ‘Software to Solve Problems in Large Computing Courses. Mark J. Canup, Georgia Institute of Tecppol6gy. ‘I. mark.canup@pobox.com
http://portal.acm.org/citation.cfm?doid=274790.273178HOME |
2y (10^x) = (10^x)^2 + 1
Move everything to the right hand side.
0 = (10^x)^2 - 2y(10^x) + 1
Treat the exponent 10^x as a variable. For now we'll call it t.
0 = t^2 - 2y(t) + 1
Use the quadratic formula.
t = [ -(-2y) +/- sqrt( (-2y)^2 - 4(1)(1) ) ] / [ 2(1) ]
t = [ 2y +/- sqrt( 4y^2 - 4 ) ] / 2
t = [ 2y +/- sqrt(4(y^2 - 1)) ] / 2
t = [ 2y +/- 2sqrt(y^2 - 1) ] / 2
Cancel the 2,
t = y +/- sqrt(y^2 - 1)
BUT t = 10^x, so
10^x = y +/- sqrt(y^2 - 1)
And changing this to logarithmic form
x = log[base 10] ( y +/- sqrt(y^2 - 1) )
So as long as
y +/- sqrt(y^2 - 1) > 0
(i.e. defined for log)
we have a solution for x.
 Help with a math problem? (Calculus)?
 car engine question how clever are you 10 points to detailed answer!!!!?
|
How to solve? (using common log)?